Quick Answer: How do you find the smallest and largest number in an array?

How do you find the smallest number in an array?

Java program to find the smallest number in an array

  1. Compare the first two elements of the array.
  2. If the first element is greater than the second swap them.
  3. Then, compare 2nd and 3rd elements if the second element is greater than the 3rd swap them.
  4. Repeat this till the end of the array.

25 апр. 2018 г.

How do you find large numbers in an array?

Java program to find the largest number in an array

  1. Compare the first two elements of the array.
  2. If the first element is greater than the second swap them.
  3. Then, compare 2nd and 3rd elements if the second element is greater than the 3rd swap them.
  4. Repeat this till the end of the array.
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25 апр. 2018 г.

How do you find the minimum and second of an array?

Let’s see the full example to find the second smallest number in java array.

  1. public class SecondSmallestInArrayExample{
  2. public static int getSecondSmallest(int[] a, int total){
  3. int temp;
  4. for (int i = 0; i
  5. {
  6. for (int j = i + 1; j
  7. {
  8. if (a[i] > a[j])

How do you find the smallest number?

To get the smallest number, we arrange the digits in ascending order. 2 smallest number using the digits 7 5 2 8 is 2578.

What is the largest element?

Atomic radii vary in a predictable way across the periodic table. As can be seen in the figures below, the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. Thus, helium is the smallest element, and francium is the largest.

How do you find the second largest number in an array?

Find 2nd Largest Number in Array using Arrays

  1. import java.util.Arrays;
  2. public class SecondLargestInArrayExample1{
  3. public static int getSecondLargest(int[] a, int total){
  4. Arrays.sort(a);
  5. return a[total-2];
  6. }
  7. public static void main(String args[]){
  8. int a[]={1,2,5,6,3,2};

How do you find the maximum difference in an array?

The task is to find the maximum difference between two elements such that the larger element appears after the smaller number. That is Arr[j]-Arr[i] is maximum such that j>i. Arr[] = { 2,1,3,8,3,19,21}. Explanation − The maximum difference is between 21 and 1 and 21 appears after 1 in the array.

How do you print the maximum value in an array?

To find the largest element,

  1. the first two elements of array are checked and the largest of these two elements are placed in arr[0]
  2. the first and third elements are checked and largest of these two elements is placed in arr[0] .
  3. this process continues until the first and last elements are checked.

What is a smallest number?

0 is the smallest whole number. W = {0,1,2,3,4… } 1 is the smallest natural number. N = {1,2,3,4…..

What is greatest and smallest number?

Thus, the greatest number is 8741. To get the smallest number, the smallest digit 1 is placed at thousands-place, next greater digit 4 at hundred’s place, still greater digit 7 at ten’s place and greatest digit 8 at one’s or units place. Thus, the smallest number is 1478.

Which is the smallest whole number?

The smallest whole number is “0” (ZERO).

How do I find the second smallest number in a list Python?

This is a Python Program to find the Second Smallest number in a list.

Problem Solution

  1. Take in the number of elements and store it in a variable.
  2. Take in the elements of the list one by one.
  3. Sort the list in ascending order.
  4. Print the last element of the list.
  5. Exit.

How do you find the first two minimum values of an array?

A Simple Solution is to sort the array in increasing order. The first two elements in sorted array would be two smallest elements. Time complexity of this solution is O(n Log n). A Better Solution is to scan the array twice.

How do you find the second smallest number?

The second smallest element can be also found by traversing the array two times. In the first traversal, the smallest element (first_smallest) in the array is found and in the second traversal, the smallest element other than the first_smallest element is found. Declare an array and input the array elements.

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